Homework Help: Physics

Posted by Jen on Monday, June 11, 2012 at 2:53pm.

Find the magnitude of the gravitational attraction force that the earth exerts on a 62-kilogram astronaut who is 8.00 X 10^7 meters away from the center of the earth.

Useful numbers: M^earth=5.98 X 10^24kg; G=6.67 X 10^-11 N*m^2kg^-2

Please walk me through your steps, don't just suggest a formula-thank you.

Physics - Elena, Monday, June 11, 2012 at 3:13pm
This is only one step - The Universal Law of Gravitation
F=G• m•M/(R)²
R= 8.00 X 10^7 m,
m=62 kg
Physics - Jen, Monday, June 11, 2012 at 3:16pm
Question though, the answer in the book says that the answer is 3.9 Newtons...do I need to convert this answer or something?
Physics - Elena, Monday, June 11, 2012 at 3:28pm
F=G• m•M/(R)² =
=6.67•10^-11•62•5.98•10^24/(8• 10^7)²=3.87 N ≈3.9 N
Physics - Jen, Monday, June 11, 2012 at 4:19pm
Fabulous! Thank you!!!

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