A 0.140 kg baseball traveling 39.0 m/s strikes the catchers mitt, which, in bringing the ball to rest, recoils backward 13cm.

Question- What is the average force applied by the ball to the glove?

*Sigma Force= mass*acceleration

Use this formula:

Force x distance = work done against mitt = Kinetic Energy change

Which leads to:
Force = (1/2)M V^2/d

If you want to start from F = m*a, you have to use an equation for the acceleration, a
a = V/t = v/[d/(v/2)] = v^2/(2d)
F = m*V^2/(2d)

To find the average force applied by the ball to the glove, we can use the equation F = ma, where F represents force, m represents mass, and a represents acceleration.

First, we need to find the acceleration of the ball. We can use the formula: acceleration = (final velocity - initial velocity) / time.

Since the ball is brought to rest, the final velocity is 0 m/s. The initial velocity is given as 39.0 m/s. However, the time is not provided in the given information.

To find the time, we need to first convert the recoil distance from centimeters to meters. 13 cm is equal to 0.13 meters.

Next, we can use the formula: distance = initial velocity * time + (1/2) * acceleration * time^2.

Since the ball started with an initial velocity of 39.0 m/s and came to rest (final velocity is 0 m/s), we can simplify the formula to: distance = (1/2) * acceleration * time^2.

Plugging in the values, we have 0.13 m = (1/2) * acceleration * time^2.

Since there are two unknowns in the equation (acceleration and time), we need additional information to solve for these variables.

Do you have any additional information?