Posted by Gloria on Monday, June 11, 2012 at 9:07am.
C(7,2)*C(8,3) ways of choosing 2 out of 7 men and 3 out of 8 women. C(n,k) = n!/[(k!)(n-k)!]
C(15,5) ways of picking 5 committee members out of 15
probability of selecting 2 men and 3 women is good over total --
C(7,2)*C(8,3)/C(15,5)
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