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September 2, 2014

September 2, 2014

Posted by **Leah** on Monday, June 11, 2012 at 5:03am.

sin(-13π/6)

cot 11π/6

cot(-14π/4)

sec 23π/6

Thanks in advance ^^; and if you'd tell me step by step on how to do problems like these I'd be grateful :D

- Math/Trig -
**Steve**, Monday, June 11, 2012 at 11:29amsin(-θ) = -sinθ

sin(θ±2kπ) = sinθ

so, sin(-13π/6) = sin(-π/6) = -1/2

tan(θ±kπ) = tanθ -- same for cot

cot(11π/6) = cot(-π/6) = -cot(π/6) = -√3

cot(-14π/4) = cot(2π/4) = cot(π/2) = 0

sec(23π/6) = sec(-π/6) = √3/2

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