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November 28, 2014

November 28, 2014

Posted by **noel** on Monday, June 11, 2012 at 12:10am.

2. feta is a second quadrant angle in standard position and tan(feta) -((sqrt5)/2) = . Find the exact value of cos(feta) .

3. θ is an angle in standard position with domain 0° <θ< 360° and cot θ -(24/7)= . Find all possible values of θ (accurate to 0.1° if necessary)

- Math (please help!) -
**noel**, Monday, June 11, 2012 at 12:53amfeta = β

- Math (please help!) -
**Steve**, Monday, June 11, 2012 at 11:37am1. draw a diagram. Legs are 1 and 3, hypotenuse is √10. If cosθ = 1/√10, sinθ = 3/√10

2. legs are √5 and 2, hypotenuse = 3. If tanθ = √5/2, cosθ = 2/3. In QII, cosθ = -2/3

3. legs are 7,24, hypotenuse =25

if cotθ < 0, θ is QII or QIV.

Arccot(24/7) = 16.26°, so

θ = 163.74° or 343.74°

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