Posted by noel on Monday, June 11, 2012 at 12:10am.
feta = β
1. draw a diagram. Legs are 1 and 3, hypotenuse is √10. If cosθ = 1/√10, sinθ = 3/√10
2. legs are √5 and 2, hypotenuse = 3. If tanθ = √5/2, cosθ = 2/3. In QII, cosθ = -2/3
3. legs are 7,24, hypotenuse =25
if cotθ < 0, θ is QII or QIV.
Arccot(24/7) = 16.26°, so
θ = 163.74° or 343.74°
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