3)A car increases its speed from 5 m/s to 35 m/s in a distance of 75 m
a)what is the acceleration of the car?
b)How long did it take the car to travel the 75 m?
someone PLEASE help me willyah!
a= (v²-vₒ²)/2•s,
v=vₒ +a•t,
t= (v-vₒ)/a.
To find the acceleration of the car, you can use the formula:
acceleration = (final velocity - initial velocity) / time taken
Given:
Initial velocity (u) = 5 m/s
Final velocity (v) = 35 m/s
We need to find the time taken. To do that, we can use another formula:
distance = (initial velocity + final velocity) / 2 * time taken
Given:
Distance = 75 m
Let's solve for acceleration first.
acceleration = (35 m/s - 5 m/s) / time taken
Now, let's solve for time taken using the formula for distance.
75 m = (5 m/s + 35 m/s) / 2 * time taken
To solve for time taken, we can rearrange the equation:
time taken = 75 m * 2 / (5 m/s + 35 m/s)
Simplifying,
time taken = 150 m / 40 m/s
time taken = 3.75 seconds
So, the answers to the questions are:
a) The acceleration of the car is (35 m/s - 5 m/s) / time taken = 8 m/s^2.
b) It took the car 3.75 seconds to travel the 75 m.