Sunday

April 20, 2014

April 20, 2014

Posted by **Math Girl** on Sunday, June 10, 2012 at 8:58pm.

- algebra -
**Steve**, Monday, June 11, 2012 at 11:51amif the speed of the boat in still water is x, and the speed of the current is c, then, remembering that distance=speed*time,

20(x-c)=10(x+c)

20x-20c=10x+10c

10x=30c

x=3c

20(2c) = 160

c = 4

so, x=12

check:

20(8) = 160

10(16) = 160

**Related Questions**

alegbra - a tugboat goes 160 miles upstream in 20 hours. The return trip ...

algebra - tugboat goes 160 miles upstream in 10 hours. The return trip ...

Algebra - A tugboat goes 160 miles up stream in 20 hours, return trip downstream...

math - A tugboat goes upstream 120 miles in 20 hours. The return trip downstream...

algebra - A tugboat goes 180 miles upstream in 15 hours. The return trip ...

MAT 116 - A tugboat goes 180 miles upstream in 10 hours. The return trip ...

math - A tugboat can go 10 miles upstream in the same time as it can go 15 miles...

alegrbra - A tugboat is going 100 miles upstream in 10 hours and returning ...

algerbia - a tugboat goes 120 miles up streem in 15 hours it takes 10 hours to ...

Math - Can someone please go over the steps to solve this problem? I know I need...