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Physics

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A tiger leaps horizontally from a 5.9 meter high rock with a speed of 3.7 m/s.

Questions: How far from the base of the rock will the tiger land?

  • Physics - ,

    H=gt²/2 => t =sqrt(2H/g) =sqrt(2•5.9/9.8) =1.1 s.
    X =v•t =3.7•1.1 = 4.07 m.

  • Physics - ,

    y=1/2at^2|
    5.9=1/2(9.8)t^2|
    1.204=t^2|
    t=1.097s|
    ___________

    x=t[(Vi+Vf)/2]
    x=1.097[(3.7+0)/2]
    x=2.03m

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