Posted by Erin on Sunday, June 10, 2012 at 12:04pm.
This could be a very complicated problem; I will assume it is to considered a simple one by ignoring the ionization of H2C2O4.
0.0061 g CaC2O4 = how many mols?
0.p0061/molar mass CaC2O4 = approximately ? = (Ca^2+) = (CO4^2-)
CaC2O4 ==> Ca^2+ + C2O4^2-
Ksp = (Ca^2+)(C2O4^2-) = ?
Substitute the molar solubilities of the ions into the Ksp expression and solve for Ksp.
i get 4.76 x 10^-5 mol CaC2o4.. squaring the answer gives me a ksp= 2 x 10^-9
is this right?
Yes and no. 2 x 10^-9 is the right start. Why did you throw the other numbers away? It's hard to tell exactly how many significant figures you have (that could be 0.00610g and you just didn't type the last zero) but the 0.0061 give you at least two so you should have at least two in the answer. My calculator shows 2.265E-9. You should round that number to the correct number of s.f.
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