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posted by Scraffii Sunday, June 10, 2012 at 6:01am.

If (x+y)^2=168 and xy =4, then x^2 + y^2=?

(x+y)^2 = 168 x^2 + 2xy + y^2 = 168 Replace xy with 4: x^2 + 2*4 + y^2 = 168 x^2 + y^2 = 168 - 8 = 160.

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