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December 18, 2014

December 18, 2014

Posted by **Kallie** on Saturday, June 9, 2012 at 12:06pm.

Between the left and right support is 0.900m and from the right support to the end of the sign is 0.300m.

------------------------------

| | --------> (0.900m)|| --->(0.300m)

I got answers: a. 111.1 and b. 186.2 but I'm not sure if they're correct. Can someone please help?

- Physics -
**Elena**, Saturday, June 9, 2012 at 6:15pmWeight of the sign is W = mg = 28.5kg•9.8m/s² = 297.3N

The sum the moments around the left bottom of the sign.

Clockwise moment Mcw = 297.3N • (1.2m/2) = 167.6 N•m

Counterclockwise moment Mccw = F•0.9m

That is, the cw rotation of the sign about the left corner is resisted by a support force.

F = 167.6N•m / 0.9m = 186.2N ← in the right column

The left support can be determined in a similar fashion, or simply by noting that it must support the remaining vertical force:

Left F = W - Fr = 297.3N - 186.2N = 111.1N ← left support

- Physics -
**Austin**, Tuesday, November 4, 2014 at 1:52pm28.5x9.80 = 279.3 not 297.3.

therefore the left support would equal 93.1 not 11.1

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