Posted by **Lilly** on Saturday, June 9, 2012 at 11:31am.

A 20 kg square slab with side lengths 3.0 m rotates around an axis perpendicular to the slab. A particle of mass 0.60 kg sits on each of the corners of the square. Also, a particle of mass 0.80 kg sits at the center of each of the edges. What is the moment of inertia of the system?

Help me please :)

- Physics! -
**Elena**, Saturday, June 9, 2012 at 5:32pm
m1=20 kg, a=3 m,

I1 =m•a²/6 = 20•9/6 =30 kg•m²

m2 =0.6 kg , b =a•√2/2=3•√2/2 =2.13 m.

I2 =mb²=0.6•2.13²= 2.7 kg•m²

m3 = 0.8 kg, c=a/2 =1.5 m.

I3=mc²=0.8• 1.5² =1.8 kg•m².

I =I1+4•I2+4•I3 = 30+4•(2.7+1.8) =48 kg•m².

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