Bob and Ray push on a door from opposite sides. They both push perpendicular to the door. Bob pushes 0.63 m from the door hinge with a force of 89 N. Ray pushes 0.57 m from the door hinge with a force of 98 N, in a manner that tends to turn the door in a clockwise direction. What is the net torque on the door?
I put 2.46n.m and got this wrong can someone please help me!
τ = 89•0.63 -98•0.57 =
=56.7-55.86 = 0.84 N•m (anticlockwise)
To calculate the net torque on the door, we need to find the torque exerted by both Bob and Ray and then add them together.
The torque exerted by an object is given by the equation:
Torque = Force x Distance x sin(θ)
Where:
- Force is the magnitude of the force applied.
- Distance is the perpendicular distance from the point of rotation (hinge) to the line of action of the force.
- θ is the angle between the force and the line of action (typically taken as 90 degrees for a perpendicular force).
Let's calculate the torque exerted by Bob first:
Torque_Bob = Force_Bob x Distance_Bob x sin(θ)
= 89 N x 0.63 m x sin(90°) [since the force is perpendicular to the door]
= 89 N x 0.63 m x 1
= 56.07 N.m
Now, let's calculate the torque exerted by Ray:
Torque_Ray = Force_Ray x Distance_Ray x sin(θ)
= 98 N x 0.57 m x sin(90°) [since the force is perpendicular to the door]
= 98 N x 0.57 m x 1
= 55.86 N.m
Now, to find the net torque, we add the torques exerted by Bob and Ray:
Net Torque = Torque_Bob + Torque_Ray
= 56.07 N.m +55.86 N.m
= 111.93 N.m
Therefore, the net torque on the door is 111.93 N.m.
It seems there was an error in your calculation. Make sure to double-check your math and ensure that you correctly multiplied the force, distance, and sin(θ) for each person.