Posted by Teri on Friday, June 8, 2012 at 2:19pm.
If the shadow is length y when the man is x feet from the pole, then using similar triangles,
y/6 = (x+y)/16
y = 3x/5
dy/dt = 3/5 dx/dt = 3/5 (-5) = -3
so, the shadow is shrinking at 3 ft/sec regardless of the distance from the pole.
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