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July 30, 2014

July 30, 2014

Posted by **Teri** on Friday, June 8, 2012 at 2:19pm.

- Math -
**Steve**, Friday, June 8, 2012 at 3:17pmIf the shadow is length y when the man is x feet from the pole, then using similar triangles,

y/6 = (x+y)/16

y = 3x/5

dy/dt = 3/5 dx/dt = 3/5 (-5) = -3

so, the shadow is shrinking at 3 ft/sec regardless of the distance from the pole.

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