maths
posted by sagar on .
1) if x+1/x=2,then x^2012+1/x^2012=?
2)if A>B>C>D,find the digits A,B,C,D (which are from1 to 9), so that
ABCDDCBA=BDAC.
3)solve:pxqy=r and rxpy=q.

x + 1/x = 2
x = 1
x^n + 1/x^n = 2 for any n
76411467=6174
x = p(prq^2)/(p^2rq)
y = (r^2pq)/(p^2rq)