physics
posted by Joseph on .
x=x0+v0t+1/2at^2. Assuming that x0=0, a=2, and x=h, solve for t in terms of initial v and h?
x0 mean initial value of x
same with v0

Assuming that x0=0, a=2, and x=h,
h = v0*t + t^2
t^2 + v0*t h = 0
t = [v0 +/sqrt(v0^2+4h)]/2