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November 29, 2014

November 29, 2014

Posted by **Jewel** on Thursday, June 7, 2012 at 9:17pm.

Suppose that the width of a rectangle is three feet shorter than length and that the perimeter of the rectangle is 86 feet.

Set up an equation for the perimeter involving only L, the length of the rectangle.

Solve this linear equation algebraically to find the length of the rectangle. Find the width as well.

Length___,width____

Using the same width from your answer or part b), find a new perimeter when the new length is five less than three times the width.

Explain the work in one or two sentences.

- Algebra -
**Henry**, Friday, June 8, 2012 at 2:54pmb. Length = L Ft.

Width = (L-3) Ft.

P = 2L + 2(L-3).

P = 2L + 2L - 6 = 86.

4L = 86 + 6 = 92

L = 23 Ft.

W = L - 3 = 32 - 3 = 29 Ft.

c. Width = 29 Ft.

Length = (3W-5) = (3*29 - 5 = 82 Ft.

P = 2L + 2W = 2*82 + 2*29 = 222 Ft.

- Algebra -
**Henry**, Friday, June 8, 2012 at 3:06pmb. Correction: W = L-3 = 23 - 3 = 20 Ft.

c. Width = 20 Ft.

Length = (3W-5) = 3*20 - 5 = 55 Ft.

P = 2L + 2W = 2*55 + 2*20 = 150 Ft.

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