Posted by garth on Thursday, June 7, 2012 at 8:27pm.
Given: Fs = 0.38, Fk = 0.28, m = ?.
Did you forget the mass?
Mass = 30kg(Assumed).
Wb = m*g = 30kg * 9.8N/kg = 294 N. =
Weight of box.
Fb = 294N @ 0 Deg. = Force of box.
Fp=294*sin(0)=0=Force parallel to floor
Fv = 294*cos(0) = 294 N. = Force perpendicular to floor.
Fn = Fp - u*Fv -u*Fv' = m*a. a = 0.
0 - 0.38*294 - 0.38Fv' = 0
-0.38Fv' = 0.38*294 = 111.72
Fv' = - 294 N.
Related Questions
physics - What is the minimum downward force on the box in the figure that will ...
physics - What is the minimum downward force on the box in the figure that will ...
physics - What is the minimum downward force on the box ( m=30 kg)that will keep...
physics - Posted by norm on Monday, March 15, 2010 at 9:21am. What is the ...
Physics - The two blocks in the figure, of mass m and M respectively, are not ...
physics - You are pushing a box up an inclined ramp. The force you exert on the ...
physics - carol and bruno drag a box of mass 58.0 kg along a frictionless floor...
Physics - The two blocks (m = 37 kg and M = 109 kg) in the figure below are not ...
physics - a 6 kg box is stacked on top of a 15 kg box. anet leans down and pulls...
Physics - A child pushes a toy box 4.0 m along the floor with a force of 6.00 N ...
For Further Reading