(4y+5)(4y-5)
16y^2-20y+20y-25
16y^2-25
Am I correct
you are correct
Yes, you are correct! The expression (4y+5)(4y-5) can be simplified using the distributive property. To solve it, you multiply each term in the first expression (4y+5) by each term in the second expression (4y-5).
First, let's multiply the first terms: 4y * 4y = 16y^2.
Next, let's multiply the two outer terms: 4y * -5 = -20y.
Now, let's multiply the two inner terms: 5 * 4y = 20y.
Finally, let's multiply the last terms: 5 * -5 = -25.
Now we can combine the like terms:
16y^2 - 20y + 20y - 25
The two middle terms, -20y and +20y, cancel each other out since they have the same magnitude but opposite signs. Thus, you are left with:
16y^2 - 25
So, your answer, 16y^2 - 25, is correct!