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March 25, 2017

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A tungsten target is struck by electrons that have been accelerated from rest through a 38.9-kV potential difference. Find the shortest wavelength of the radiation emitted.

  • Physics please help! - ,

    For Bremsstrahlung radiation (or "braking X- radiation" )
    the low-wavelength cutoff may be determined from Duane–Hunt law :
    λ =h•c/e•U,
    where h is Planck's constant, c is the speed of light, V is the voltage that the electrons are accelerated through, e is the elementary charge
    λ = 6.63•10^-34•3•10^8/1.6•10^-19•3.89•10^4 = 3.19•10^-11 m.

  • Notation got messed up - ,

    λ = 6.63•10^-34•3•10^8/1.6•10^-19•3.89•10^4 = 3.19•10^-11 m.

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