Posted by Gracie on .
A tungsten target is struck by electrons that have been accelerated from rest through a 38.9-kV potential difference. Find the shortest wavelength of the radiation emitted.
Physics please help! -
For Bremsstrahlung radiation (or "braking X- radiation" )
the low-wavelength cutoff may be determined from Duane–Hunt law :
where h is Planck's constant, c is the speed of light, V is the voltage that the electrons are accelerated through, e is the elementary charge
λ = 6.63•10^-34•3•10^8/1.6•10^-19•3.89•10^4 = 3.19•10^-11 m.
Notation got messed up -
Î» = 6.63â€¢10^-34â€¢3â€¢10^8/1.6â€¢10^-19â€¢3.89â€¢10^4 = 3.19â€¢10^-11 m.