Posted by echo on Thursday, June 7, 2012 at 9:35am.
if alpha and beta are the zeros of the polynomial 2x^24x+5 then find the values of
(i)alpha^2+beta^2
(ii)1/alpha^2+1/beta^2
(iii)(r)alpha/beta+(r)beta/alpha
(iv)alpha^1+beta^1

maths  MathMate, Thursday, June 7, 2012 at 10:31am
The general solution to the equation
ax^2+bx+c=0
is, using the quadratic formula:
α=(b+√(b²4ac))/2a, and
β=(b√(b²4ac))/2a
From there, expand α²+β² to get (b²2ac)/a²
I will leave parts (ii) to (iv) for you as practice.
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