maths
posted by echo on .
if alpha and beta are the zeros of the polynomial 2x^24x+5 then find the values of
(i)alpha^2+beta^2
(ii)1/alpha^2+1/beta^2
(iii)(r)alpha/beta+(r)beta/alpha
(iv)alpha^1+beta^1

The general solution to the equation
ax^2+bx+c=0
is, using the quadratic formula:
α=(b+√(b²4ac))/2a, and
β=(b√(b²4ac))/2a
From there, expand α²+β² to get (b²2ac)/a²
I will leave parts (ii) to (iv) for you as practice. 
alpha+beta=b/a
=4/2
=2
alpha^2+beta^2=(alpha+beta)^2
=2^2
=4
(ii)take reciprocal(1/2)^2=1/4
(iv)a^1=1/a similarly 1/2
tried my best to answer hope its correct:)
your pal
mathew