Friday

August 22, 2014

August 22, 2014

Posted by **echo** on Thursday, June 7, 2012 at 9:35am.

(i)alpha^2+beta^2

(ii)1/alpha^2+1/beta^2

(iii)(r)alpha/beta+(r)beta/alpha

(iv)alpha^-1+beta^-1

- maths -
**MathMate**, Thursday, June 7, 2012 at 10:31amThe general solution to the equation

ax^2+bx+c=0

is, using the quadratic formula:

α=(-b+√(b²-4ac))/2a, and

β=(-b-√(b²-4ac))/2a

From there, expand α²+β² to get (b²-2ac)/a²

I will leave parts (ii) to (iv) for you as practice.

**Related Questions**

Math ( Polynomial ) - This time three questions - 1. If (x^2 - 1 ) is a factor ...

Math ( Polynomial ) - This time three questions - 1. If (x^2 - 1 ) is a factor ...

Math - If alpha and beta are the zeros of the polynomial ax^2 + bx + c then ...

trig - evaluate the following in exact form, where the angeles alpha and beta ...

maths - If alpha and beta are the zeros of the polynomial p(x)=x^2+x+1 then find...

Calculus - The question will first read in English followed by a reading in ...

physics - Two radar stations A and B, are separated by horizontal distance of (...

Math - how i solve this two equations ib order to find alpha and beta 2=cos(...

maths - If alpha beta are the roots of a^2 +bx + c = 0. find the values of (beta...

Math - Given that sin alpha=4/sqrt65, pi/2<alpha<pi, and cos beta=-3/...