Posted by Mackenzie on Thursday, June 7, 2012 at 8:40am.
1.) Determine the equation of the axis of symmetry.
y = -5x2 - x + 9
Answer 1.) x=3/2
2.) Determine the equation of the axis of symmetry.
y = -6x2 + 3x - 4
Answer 2.) x=-2/10
- Algebra 1B--Check Please! - MathMate, Thursday, June 7, 2012 at 10:08am
I assume you have not done calculus before.
To find the axis of symmetry of a polynomial of second degree (quadratic), we only have to complete the squares, which will then give the coordinates of the vertex in the form V(h,k) where
and a is another constant.
y = -5x2 - x + 9
Therefore h=-1/10, k=9.05, and
or the axis of symmetry is x=-1/10
I will leave #2 for you as practice.
- Algebra 1B--Check Please! - Mackenzie, Thursday, June 7, 2012 at 10:17am
Thanks! so number two is wrong?
- Algebra 1B--Check Please! - MathMate, Thursday, June 7, 2012 at 10:33am
#2 is not correct.
You can follow the steps above and try again.
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