Posted by Mackenzie on .
1.) Determine the equation of the axis of symmetry.
y = 5x2  x + 9
Answer 1.) x=3/2
2.) Determine the equation of the axis of symmetry.
y = 6x2 + 3x  4
Answer 2.) x=2/10

Algebra 1BCheck Please! 
MathMate,
I assume you have not done calculus before.
To find the axis of symmetry of a polynomial of second degree (quadratic), we only have to complete the squares, which will then give the coordinates of the vertex in the form V(h,k) where
y=a(xh)²+k
and a is another constant.
Starting with
y = 5x2  x + 9
we write
y=5(x²+2(x/10))+9
=5(x+1/10)²+5/100 +9
=5(x+1/10)² +9.05
Therefore h=1/10, k=9.05, and
V(1/10,9.05)
or the axis of symmetry is x=1/10
I will leave #2 for you as practice. 
Algebra 1BCheck Please! 
Mackenzie,
Thanks! so number two is wrong?

Algebra 1BCheck Please! 
MathMate,
#2 is not correct.
You can follow the steps above and try again.