Posted by **Mackenzie** on Thursday, June 7, 2012 at 8:40am.

1.) Determine the equation of the axis of symmetry.

y = -5x2 - x + 9

Answer 1.) x=3/2

2.) Determine the equation of the axis of symmetry.

y = -6x2 + 3x - 4

Answer 2.) x=-2/10

- Algebra 1B--Check Please! -
**MathMate**, Thursday, June 7, 2012 at 10:08am
I assume you have not done calculus before.

To find the axis of symmetry of a polynomial of second degree (quadratic), we only have to complete the squares, which will then give the coordinates of the vertex in the form V(h,k) where

y=a(x-h)²+k

and a is another constant.

Starting with

y = -5x2 - x + 9

we write

y=-5(x²+2(x/10))+9

=-5(x+1/10)²+5/100 +9

=-5(x+1/10)² +9.05

Therefore h=-1/10, k=9.05, and

V(-1/10,9.05)

or the axis of symmetry is x=-1/10

I will leave #2 for you as practice.

- Algebra 1B--Check Please! -
**Mackenzie**, Thursday, June 7, 2012 at 10:17am
Thanks! so number two is wrong?

- Algebra 1B--Check Please! -
**MathMate**, Thursday, June 7, 2012 at 10:33am
#2 is not correct.

You can follow the steps above and try again.

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