Thursday
October 2, 2014

Homework Help: calculus (check my work please)

Posted by Jay on Thursday, June 7, 2012 at 12:15am.

Not sure if it is right, I have check with the answer in the book and a few integral calculators but they seem to get a different answer

∫ sec^3(x)tan^3(x) dx
∫ sec^3(x)tan(x)(sec^2(x)-1) dx
∫ tan(x)sec(x)[sec^4(x)-sec^2(x)] dx
∫ tan(x)sec(x)[(tan^2(x)+1)^2-tan^2(x)-1] dx
∫ tan(x)sec(x)(1+2tan(x)+tan^2(x)-tan^2(x)-1) dx
∫ 2tan^2(x)sec(x) dx
∫ 2(sec^2(x)-1)sec(x) dx
∫ 2sec^3(x)-2sec(x) dx
2∫ sec^3(x) dx -2∫ sec(x) dx
*reduction formula
2tan(x)sec(x)-ln(tan(x)+sec(x))

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