Posted by Jay on Thursday, June 7, 2012 at 12:15am.
Not sure if it is right, I have check with the answer in the book and a few integral calculators but they seem to get a different answer
∫ sec^3(x)tan^3(x) dx
∫ sec^3(x)tan(x)(sec^2(x)1) dx
∫ tan(x)sec(x)[sec^4(x)sec^2(x)] dx
∫ tan(x)sec(x)[(tan^2(x)+1)^2tan^2(x)1] dx
∫ tan(x)sec(x)(1+2tan(x)+tan^2(x)tan^2(x)1) dx
∫ 2tan^2(x)sec(x) dx
∫ 2(sec^2(x)1)sec(x) dx
∫ 2sec^3(x)2sec(x) dx
2∫ sec^3(x) dx 2∫ sec(x) dx
*reduction formula
2tan(x)sec(x)ln(tan(x)+sec(x))

calculus (check my work please)  Bosnian, Thursday, June 7, 2012 at 12:47am
In google type:
wolfram alpha
When you see lis of results click on:
Wolfram Alpha:Computational Knowledge Engine
When page be open in rectangle type:
integrate sec^3(x)tan^3(x) dx
and click option =
After few secons you will see result.
Then click option Show steps

calculus (check my work please)  Jay, Thursday, June 7, 2012 at 12:52am
I did, I got a completely different result. Also, SAY SOMETHING USEFUL NEXT TIME!!! tired of you spamming that stupid reply

calculus (check my work please)  Bosnian, Thursday, June 7, 2012 at 1:06am
Try to simplify your "different answers".
Probably your "different answers" is same solutions write in different form.

calculus (check my work please)  Jay, Thursday, June 7, 2012 at 2:19am
right, because my answer can be simplified into:
sec^5(x)/5sec^3(x)/3
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