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Algebra

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The width of a rectangle is three fourths of the length. The perimeter of the rectangle becomes 50 cm when the legth and the width are each increased by two cm. Find the length and the width

  • Algebra - ,

    Looks like a case for substitution.

    width = w
    length = l

    width = 3/4 length
    w = 3/4l

    2(w + 2) + 2(l + 2) = 50cm
    (2w + 4) + (2l + 4) = 50cm

    Substitute w with the information you were given earlier (the width of a rectangle is three fourths the length):

    2(3/4l) + 4 + 2l + 4 = 50cm
    2(3/4l) + 2l + 8 = 50cm
    6/4l + 2l = 42cm
    1.5l + 2l = 42cm
    3.5l = 42cm
    l = 12cm

    3/4(12cm) = 9cm

    length = 12cm
    width = 9cm

  • Algebra - ,

    what is the perimeter of the rectangle w/ length x+4/x+3 and width 2x-3/x+3

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