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October 20, 2014

October 20, 2014

Posted by **angela** on Wednesday, June 6, 2012 at 10:25pm.

and two consolation prizes of $50 each will be awarded. Jeremy purchases one ticket. Find his expected value. Show your work for full credit.

- geometry -
**MathMate**, Wednesday, June 6, 2012 at 10:36pmExpected value for a probability distribution is

E(x)=∑xP(x)

In this case,

P(200)=1/1000

P(50)=2/1000

P(other prizes)=0/1000

Calculate E(x)

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