Calculate the mass of ammonia salt that would remain if the solution were evaporated to dryness. When sulfuric acid reacts with ammonia solution an ammonium salt is produced.
21.4g
See your post above. There isn't enough info.
To calculate the mass of ammonia salt remaining after the solution is evaporated to dryness, we need to know the molar ratio between sulfuric acid and ammonia and the initial concentration of ammonia solution.
Step 1: Write the balanced chemical equation for the reaction between sulfuric acid (H2SO4) and ammonia (NH3):
H2SO4 + 2NH3 → (NH4)2SO4
From the equation, we can see that one mole of sulfuric acid reacts with two moles of ammonia to produce one mole of ammonium sulfate.
Step 2: Determine the molar ratio between sulfuric acid and ammonia. In this case, it is 1:2.
Step 3: Determine the initial concentration of ammonia solution. Let's assume it is "C" mol/L.
Step 4: Calculate the number of moles of ammonia in the solution before the reaction.
Number of moles of ammonia = concentration of ammonia × volume of solution in liters
Step 5: Use the molar ratio to calculate the number of moles of ammonium sulfate formed.
Number of moles of ammonium sulfate = (number of moles of ammonia × 1) / 2
Step 6: Calculate the mass of ammonium sulfate:
Mass of ammonium sulfate = number of moles of ammonium sulfate × molar mass of (NH4)2SO4
Step 7: The mass of ammonium sulfate obtained in Step 6 is the mass of ammonia salt that would remain if the solution were evaporated to dryness.
Note: It's important to take into account the solubility of the ammonium salt when evaporating the solution. If the salt is highly soluble, it may not form solid crystals even after evaporation.