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Math

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Michael purchased a certain number of share of one stock for a total of $2800. The second stock was selling for $6 less per share . Michael could have bought 6 more shares of the second stock for the same amount of money. How many shares of the first stock did Michael purchase? How much did each share cost?

  • Math - ,

    Say he bought n shares for $x of 1st stock.

    nx = 28000
    (n+6)(x-6) = 28000

    nx+6x-6n-36 = 28000
    we know nx=28000, so
    6x-6n = 36
    x-n=6
    now, n=28000/x, so
    x - 28000/x = 6
    x^2 - 6x - 28000 = 0
    x = 3±√28009
    x = 170.36

    164.36*170.36 = 28000.37
    170.36*164.36 = 28000.37

    Odd that the solution was not integers

  • Math - ,

    she bought 50 shares at the cost of 56. Yay

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