Posted by **Jasmine** on Wednesday, June 6, 2012 at 1:08am.

Michael purchased a certain number of share of one stock for a total of $2800. The second stock was selling for $6 less per share . Michael could have bought 6 more shares of the second stock for the same amount of money. How many shares of the first stock did Michael purchase? How much did each share cost?

- Math -
**Steve**, Wednesday, June 6, 2012 at 12:25pm
Say he bought n shares for $x of 1st stock.

nx = 28000

(n+6)(x-6) = 28000

nx+6x-6n-36 = 28000

we know nx=28000, so

6x-6n = 36

x-n=6

now, n=28000/x, so

x - 28000/x = 6

x^2 - 6x - 28000 = 0

x = 3±√28009

x = 170.36

164.36*170.36 = 28000.37

170.36*164.36 = 28000.37

Odd that the solution was not integers

- Math -
**shujaat. Shani**, Friday, November 29, 2013 at 6:23pm
she bought 50 shares at the cost of 56. Yay

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