Posted by **Anonymous** on Tuesday, June 5, 2012 at 11:36pm.

Water is flowing at a rate of 50 cubic meters per minute into a holding tank shaped like a cone, sitting vertex down. The tank's base diameter is 40 m and a height of 10 m.

Write an expression for the rate of change of the water level with respect to time, in terms of h (the water's height in the tank).

- CALCULUS - PLEASE HELP -
**Steve**, Wednesday, June 6, 2012 at 12:29pm
using similar triangles, the radius of the water surface at height h can be found

r/h = (40/2)/10 = 2

so, r = 2h

v = 1/3 π r^2 h

= π/3 (2h)^2 h

= 4π/3 h^3

dv/dt = 4π h^2 dh/dt

50 = 4π h^2 dh/dt

dh/dt = 25/(2πh^2)

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