Posted by **Anonymous** on Tuesday, June 5, 2012 at 9:51pm.

I am trying to solve 0=1-asin(a) for a, but I have reached a dead end at sin(a) = 1/a. From here I'm not sure what to do.

- CALCULUS - HELP -
**MathMate**, Tuesday, June 5, 2012 at 10:13pm
asin(a)-1=0

asin(a)=1

a=(2k+1/2)π where k=integer

Use the graph of sin(x) to solve for a.

Note:

asin(a) does NOT equal 1/sin(a).

asin(a)=x means sin(x)=a

- CALCULUS - HELP -
**Anonymous**, Tuesday, June 5, 2012 at 10:27pm
I think I should restate this, I am trying to solve 0=1-a(sin(a). I didn't mean asin to mean arcsin, it's supposed to be a(sin(a)).

- CALCULUS - HELP -
**MathMate**, Tuesday, June 5, 2012 at 11:35pm
Are you doing Calculus or pre-calculus?

I believe that to solve for

sin(x)=1/x

requires numerical methods, such as Newton's method, or other approximation methods.

You can also plot sin(x) and 1/x and see where they intersect or as approximations.

See:

http://img543.imageshack.us/img543/7304/1338947466.png

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