Posted by Amber on Tuesday, June 5, 2012 at 6:59pm.
Vp = 200mi/h @ 180.
Vw = 25mi/h @ 240 Deg.
1. X=Hor=200*cos180+25*cos240=-212.5 mi/h
Y=Ver=200*sin180+25*sin240=-21.65mi/h
Vp=sqrt((-212.50^2)+(-21.65)^2)=213.6
= Velocity of plane.
2. tanA = Y/X = -21.65 / -212.5 = 0.10188.
A = 5.8 Deg. = Smallest angle.
3. C = 90 = Largest angle.
4. B=90-5.8 = 84.2 Deg.= Remaining angle.
5. Bearing = 180 + 5,8=185.8 Deg.,CCW
= 5.8 Deg. South of West
4. C = 180 - 5.8 - 84.2 = 90 Deg
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