Posted by Stewart on Tuesday, June 5, 2012 at 6:58pm.
xy = (xy - x)^(1/2)
x dy/dx + y = (1/2)(xy - x)^(-1/2) (xdy/dx + y - 1)
so at (1,2)
dy/dx + 2 = (1/2)(2 - 1)^(-1/2) (dy/dx + 2 - 1)
times 2
2dy/dx + 4 = (1)(dy/dx + 1)
dy/dx = 1-4 = -3
so tangent is y = -3x + b
with (1,2) lying on it
2 = -3+b
b=5
tangent equation:
y = -3x + 5
check my arithmetic
Related Questions
COLLEGE CALCULUS. - Use implicit differentiation to find the equation of the ...
Calculus - I am unsure of how to take the derivative of this equation. It may be...
math calculus - Use implicit differentiation to find the equation of the tangent...
math - Use implicit differentiation to find the equation of the tangent line to ...
Calculus - If the equation of the tangent line to the curve: xy^3+xy=6, (3,1) ...
calculus - Find the equation of the tangent line to the curve x^3 + xy^2 =5 at ...
Calculus - Find the equation of the tangent line to the curve 2e^(xy) = x + y at...
Calculus - Please help this is due tomorrow and I dont know how to Ive missed a ...
math - for the curve y^3+(1/2)xy=1 find a formula for dy/dx in terms of x and y ...
Calculus ap - Use implicit differentiation to find the slope of the tangent line...
For Further Reading
