Posted by **matematicass** on Tuesday, June 5, 2012 at 5:19pm.

what angle between vectors u = 2j+2k & v= 3i+4k

Gracias por ayudarme

- math -
**Steve**, Tuesday, June 5, 2012 at 5:33pm
u.v = |u| * |v| * cosθ

cosθ = (6+8)/(2√2)(5) = 14/10√2

θ = 8.13°

- math -
**Count Iblis**, Tuesday, June 5, 2012 at 5:34pm
u dot v = |u| |v| cos(theta)

u dot v = 6

|u| = 2 sqrt(2)

|v| = 5

cos(theta) = 3/[5 sqrt(2)]

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**Count Iblis**, Tuesday, June 5, 2012 at 5:36pm
Correction u dot v = 8, so

cos(theta) = 4/[5 sqrt(2)]

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**matematicas**, Tuesday, June 5, 2012 at 6:47pm
but isn't is a three dimensional vectors

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**Steve**, Wednesday, June 6, 2012 at 12:40pm
my bad. I misread the problem.

Count Iblis is correct.

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