The length of the side of a rectangle desk is given by 2x-6y cm. The lenght of the front is given by 2x+6y cm. What is an algebraic expression for the area of the top of the rectangular desk? Include correct units as part of your answer.
Given: 2x+6ycm, 2x-6ycm.
A = 2x.
A^2 = 4x^2.
B = 6y.
B^2 = 36y^2.
Area=(A+B)(A-B)=A^2-B^2=4x^2-36y^2 cm^2