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Average Value - Calculus

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What is the average value of y for the part of the curve y = 4x − x^3 that is in the first quadrant?

  • Average Value - Calculus -

    since there are roots at 0 and 2, integrate from 0 to 2 and divide by the interval length (2).

    (2x^2 - 1/4 x^4)[0,2]/2 = 4/2 = 2

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