Post a New Question

Average Value - Calculus

posted by on .

What is the average value of y for the part of the curve y = 4x − x^3 that is in the first quadrant?

  • Average Value - Calculus - ,

    since there are roots at 0 and 2, integrate from 0 to 2 and divide by the interval length (2).

    (2x^2 - 1/4 x^4)[0,2]/2 = 4/2 = 2

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question