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January 31, 2015

January 31, 2015

Posted by **ANONYMOUS** on Tuesday, June 5, 2012 at 2:02pm.

- CALCULUS -
**Steve**, Tuesday, June 5, 2012 at 2:25pmsure, I have an idea. Find the derivative to get the slope of the tangent line! Then use the point-slope form of the line's equation:

y = (5x-1)/(3x+1)

y(1) = 4/4 = 1

y' = 8/(3x+1)^2

y'(1) = 8/16 = 1/2

tangent line is thus

(y-1) = 1/2 (x-1)

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