Calculus
posted by
Aria on
.
Differentiate x^2y^3+x^3y^4=11 implicitly to find dy/dx.

Calculus 
Steve,
2xy^3 + 3x^2y^2y' + 3x^2y^4 + 4x^3y^3y' = 0
y' = (2xy^3 + 3x^2y^4)/(3x^2y^2 + 4x^3y^3)
= (2y + 3xy^2)/(3x + 4x^2y)
assuming x,y not zero

Calculus 
Aria,
Thanks a lot, it makes so much more sense now! :)