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December 21, 2014

December 21, 2014

Posted by **Labz** on Monday, June 4, 2012 at 5:54pm.

- Math -
**Reiny**, Monday, June 4, 2012 at 7:02pmlet f(x) = x^3 - 4x^2 + x + 6

f(1) = 1-4+1+6 ≠0

f(-1) = -1 - 4 -1 + 6 = 0

so (x+1) is a factor

Using synthetic division or long algebraic division

x^3 - 4x^2 + x + 6

= (x+1)(x^2 - 5x + 6)

= (x+1)(x-6)(x+1)

so x = 6 or x = -1 (a double root at x=-1)

- Math -
**Labz**, Monday, June 4, 2012 at 7:07pmthank you!

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