5)suppose in the previous question when timmy is sitting at rest he has 40j of GPE then his dad gives timmy a big push when his dad lets go. Timmy has 60j of GPE and 120j of KE
A) before his dad pushed him GPE____ KE___ Te___
B) immedalety after his dad pushed him GPE___ KE___ TE___
C) how much work did Timmys dad do when he pushed timmy?
D) at the top of timmys path GPE___ KE____TE_____
E) he swing back down through the bottom of his path GPE_____ KE____ TE____
F) Timmy jumps off the swing just before he lands GPE____ KE_____ TE______
G) Timmy hit the ground
GPE____ KE____ TE____
To answer these questions, we need to understand the concepts of Gravitational Potential Energy (GPE), Kinetic Energy (KE), and Total Energy (TE).
A) Before Timmy's dad pushed him:
- GPE = 40J (given)
- KE = 0J (he is at rest)
- TE = GPE + KE = 40J + 0J = 40J
B) Immediately after Timmy's dad pushed him:
- GPE = 60J (given after the push)
- KE = 120J (given after the push)
- TE = GPE + KE = 60J + 120J = 180J
C) To find out how much work Timmy's dad did, we need to calculate the change in Total Energy (ΔTE). The work done is equal to the change in energy. Therefore,
- Work done by Timmy's dad = ΔTE = TE (after the push) - TE (before the push)
- Work done by Timmy's dad = 180J - 40J = 140J
D) At the top of Timmy's path:
- GPE = ? (not given, but we know it will be less than 60J since he is lower than his initial position)
- KE = ? (not given, but we expect it to be some part of the initial KE since he has lost energy due to friction or air resistance)
- TE = GPE + KE = ? + ? = ?
E) As Timmy swings back down through the bottom of his path:
- GPE = ? (not given, but we expect it to be higher than 0J since he is higher than the ground)
- KE = ? (not given, but we know it will be less than 120J since he is losing energy due to friction or air resistance)
- TE = GPE + KE = ? + ? = ?
F) Just before Timmy jumps off the swing:
- GPE = ? (not given, but we expect it to be some value higher than 0J since he is higher than the ground)
- KE = ? (not given, but it will be some value lower than the initial KE since he has lost energy due to friction or air resistance)
- TE = GPE + KE = ? + ? = ?
G) When Timmy hits the ground:
- GPE = 0J (at ground level, all GPE is converted to other forms of energy)
- KE = ? (The remaining energy, since GPE is 0J, should be the same as the initial GPE)
- TE = GPE + KE = 0J + ? = ?
Note that for questions D, E, F, and G, the specific values for GPE and KE cannot be calculated without additional information about the loss of energy due to friction or air resistance.
A) Before his dad pushed him:
GPE = 40 J
KE = 0 J
Total energy (Te) = GPE + KE = 40 J + 0 J = 40 J
B) Immediately after his dad pushed him:
GPE = 60 J
KE = 120 J
Total energy (Te) = GPE + KE = 60 J + 120 J = 180 J
C) The work Timmy's dad did when he pushed Timmy can be calculated using the equation:
Work = Change in Energy (Te2 - Te1)
Work = 180 J - 40 J = 140 J
D) At the top of Timmy's path:
GPE = 60 J
KE = 0 J
Total energy (Te) = GPE + KE = 60 J + 0 J = 60 J
E) As he swings back down through the bottom of his path:
GPE = 0 J
KE = 120 J
Total energy (Te) = GPE + KE = 0 J + 120 J = 120 J
F) Just before he lands after jumping off the swing:
GPE = 40 J
KE = 0 J
Total energy (Te) = GPE + KE = 40 J + 0 J = 40 J
G) Timmy hits the ground:
GPE = 0 J
KE = 0 J
Total energy (Te) = GPE + KE = 0 J + 0 J = 0 J