Posted by Abhishek on Monday, June 4, 2012 at 7:25am.
y = √(lnx+√(lnx+√(lnx+...)))
y^2 = lnx+√(lnx+√(lnx+...))) = lnx + y
2y y' = 1/x + y'
(2y-1)y' = 1/x
y' = 1/(x(2y-1))
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