The ratio of the cost of an adult ticket to a student ticket for the circus is 5:3. If $32 is the total spent on tickets, how much was each adult ticket and how much was each student ticket?

Divide 32 into 5+3 parts of $4 each, so the tickets cost

5*4 = 20 and 3*4 = 12

oh yeah

To find out the cost of each adult ticket and each student ticket, we can use the concept of ratios.

Let's assume that the cost of an adult ticket is $5x, where x is a constant. Similarly, let's assume that the cost of a student ticket is $3x.

According to the given information, the ratio of the cost of an adult ticket to a student ticket is 5:3. So, we can set up the equation:

(5x)/(3x) = 5/3

Now, we can cross-multiply to solve for x:

3 * 5x = 5 * 3x

15x = 15x

This equation tells us that x can be any value since the x terms cancel out. So, let's assume x = 1 for simplicity.

Now, we can substitute the value of x back into our assumptions:

Adult ticket cost = 5x = 5 * 1 = $5
Student ticket cost = 3x = 3 * 1 = $3

Therefore, each adult ticket costs $5 and each student ticket costs $3.