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Posted by on Sunday, June 3, 2012 at 7:26pm.

Can someone please help me find the derivative of the following:

y = (-9e^7x) / (5x+3)

Thank you!

  • Math - , Sunday, June 3, 2012 at 7:54pm

    y = (-9e^7x)/(5x+3)

    y' = -9(35x^2+21x+3)*e^7x / (5x+3)^20

  • Math - , Sunday, June 3, 2012 at 7:56pm

    Use the quotient rule:
    d(u/v)=(vdu-udv)/v²
    u=(-9e^(7x))
    du/dx=-63e^7x
    dv/dx=5
    so
    d(u/v)=((5x+3)(-63e^(7x))+9e^(7x)(5))/(5x+3)^2
    =-9(35x+16)e^(7x)/(5x+3)²

  • Math - , Sunday, June 3, 2012 at 8:25pm

    typo
    There is typo
    I do not know where I got power 20

    -9( 35x+ 16 ) * e^7x /(5x+3)^2

  • Math - , Sunday, June 3, 2012 at 8:43pm

    Thank you guys!

  • Math :) - , Sunday, June 3, 2012 at 9:00pm

    You're welcome!

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