Math
posted by Francesca .
Can someone please help me find the derivative of the following:
y = (9e^7x) / (5x+3)
Thank you!

y = (9e^7x)/(5x+3)
y' = 9(35x^2+21x+3)*e^7x / (5x+3)^20 
Use the quotient rule:
d(u/v)=(vduudv)/v²
u=(9e^(7x))
du/dx=63e^7x
dv/dx=5
so
d(u/v)=((5x+3)(63e^(7x))+9e^(7x)(5))/(5x+3)^2
=9(35x+16)e^(7x)/(5x+3)² 
typo
There is typo
I do not know where I got power 20
9( 35x+ 16 ) * e^7x /(5x+3)^2 
Thank you guys!

You're welcome!