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July 1, 2015

July 1, 2015

Posted by **James** on Sunday, June 3, 2012 at 7:24pm.

l = change in length

Length = 10 cm

Cross-Sectional Area = 1 cm2

Young's Modulus = 200 GPa

Applied Load = 1000 kN

Find answer in cm.

The answer is 0.5 cm; however, I cannot figure out how to find this answer. Any help is appreciated.

- Science/Biomaterials -
**bobpursley**, Sunday, June 3, 2012 at 8:43pmLengthchange= length*load/Y *1/area

= .1m*1000kN/200GN/m^2*1/1E-4m^2=

=.1*1E6/200E9 *1/E-4=.1/2 * 1E(6-11+4)

= .05E-1 m=.5cm

- Science/Biomaterials -
**James**, Sunday, June 3, 2012 at 9:07pmWhere did you find this equation? I didn't find anything like that.