is x^3 +8 factorable?
hint:
x^3+y^3=(x+y)(x²-xy+y²)
Set x=x, y=2 to get your factors.
Yes, x^3 + 8 is factorable.
To determine the factors of x^3 + 8, we can use the factoring formula for the sum of cubes. The formula states that a^3 + b^3 can be factored as (a + b)(a^2 - ab + b^2).
In this case, a = x and b = 2. So, we can rewrite x^3 + 8 as:
(x)^3 + 2^3
Using the factoring formula, we have:
(x + 2)(x^2 - 2x + 4)
Therefore, x^3 + 8 is factorable as (x + 2)(x^2 - 2x + 4).