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Homework Help: Physics(Please help)

Posted by Hannah on Sunday, June 3, 2012 at 11:52am.

A skier slides horizontally along the snow for a distance of 11.9 m before coming to rest. The coefficient of kinetic friction between the skier and the snow is 0.0458. Initially, how fast was the skier going?

I do not know how to start this. Thank you.



Physics(Please help) - Elena, Saturday, June 2, 2012 at 8:59am
ΔKE =KE2 KE1 = 0 -mv/2.
W(fr) =μmgscosα,
where α is the angle between the friction force and displacement.
α =180, cos α = -1.
-mv/2 = - μmgs,
v = sqrt(2μ gs).




So for v would I do sqrt(2*11.9*9.8*0.0458) ?

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