how to calculate molar concentration of a 500 millimeter solution that contains 20 gram of CaBr2 ?

plz ans ma question i am in a big trouble with chemistry

first convert the volume into Liter by dividing it by 1000.

convert 20 grams of CaBr2 by its molar mass into moles.
(20 grams CaBr2)(1mol of CaBr2/199.89 g) = 0.100 mole CaBr2
Molarity is moles/ liters
= 0.100 moles/0.5L = 0.200M

how we know that 1 mol of cabr2 is 199.89 ?

To calculate the molar concentration of a solution, you'll need to know the amount of solute in moles and the volume of the solution in liters.

Here's how you can calculate the molar concentration (also known as molarity) of a solution containing 20 grams of CaBr2 in a 500 milliliter solution:

Step 1: Determine the molar mass of CaBr2. This compound consists of calcium (Ca) with a molar mass of 40.08 g/mol and two bromine atoms (Br) with a molar mass of 79.90 g/mol each. Therefore, the molar mass of CaBr2 is:
Molar mass of CaBr2 = (1 x Molar mass of Ca) + (2 x Molar mass of Br)
Molar mass of CaBr2 = (1 x 40.08 g/mol) + (2 x 79.90 g/mol)
Molar mass of CaBr2 = 159.88 g/mol

Step 2: Convert the given mass of CaBr2 from grams to moles using the formula:
Number of moles = Mass / Molar mass

Number of moles of CaBr2 = 20 g / 159.88 g/mol
Number of moles of CaBr2 ≈ 0.125 moles

Step 3: Convert the volume of the solution from milliliters to liters:
Volume of solution = 500 mL = 500 / 1000 L
Volume of solution = 0.5 L

Step 4: Finally, calculate the molar concentration (molarity) using the formula:
Molarity (M) = Number of moles / Volume of solution

Molarity (M) = 0.125 moles / 0.5 L
Molarity (M) = 0.25 M

Therefore, the molar concentration of the 500 milliliter solution containing 20 grams of CaBr2 is approximately 0.25 M.