Posted by Vilma on Sunday, June 3, 2012 at 12:02am.
Assume a linear relationship of:
F=mK+b ....(1)
where m=slope, and b=intercept.
We have two given points, (271.89,30) and (307.44,94)
The standard formula for m (slope) is:
m=(y2-y1)/(x2-x1)=(94-30)/(307.44-271.89)=1.8
With m=1.8, substitute one of the points into equation (1) to find b:
30=1.8(271.89)+b
b=30-1.8(271.89)=-459.4
So the conversion equation is:
F=1.8K-459.4
I leave it to you to substitute K=212 in order to find the fahrenheit degrees.
Let F = aK + b , (treating it like the linear equation y = mx + b)
we have two points (271.89, 30) and (307.44, 94)
a = slope = (94-30)/(307.44 - 271.89) = 64/35.55
= 1.80028
let's go with 1.8
so F = 1.8K + b
sub in (271.89,30) to find b
30 = 1.8(271.89) + b
b = -459.48
F = 1.8K - 459.48
so when K = 212
F = 1.8(212) - 459.48 = -77.9° Fahrenheit
What's that saying again, some kind of minds thinking alike ?? lol
Great minds think alike! haha!
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