Thursday

July 31, 2014

July 31, 2014

Posted by **al** on Saturday, June 2, 2012 at 8:21pm.

- calculus -
**MathMate**, Saturday, June 2, 2012 at 8:40pmlim_(theta->0)(cos(6 theta)tan(6 theta))/(theta)

=Lim (θ→0)[cos(6θ)sin(6θ)/cos(6θ)]/θ

=Lim [6 (sin(6θ)/6θ)]

=Lim [6*1]

=6

Note:

Lim sin(x)/x =1

x→0

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