Posted by al on Saturday, June 2, 2012 at 8:21pm.
lim_(theta->0)(cos(6 theta)tan(6 theta))/(theta)
=Lim (θ→0)[cos(6θ)sin(6θ)/cos(6θ)]/θ
=Lim [6 (sin(6θ)/6θ)]
=Lim [6*1]
=6
Note:
Lim sin(x)/x =1
x→0
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