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posted by al Saturday, June 2, 2012 at 8:21pm.
lim_(theta->0)(cos(6 theta)tan(6 theta))/(theta)
lim_(theta->0)(cos(6 theta)tan(6 theta))/(theta) =Lim (θ→0)[cos(6θ)sin(6θ)/cos(6θ)]/θ =Lim [6 (sin(6θ)/6θ)] =Lim [6*1] =6 Note: Lim sin(x)/x =1 x→0
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