calculate3 the concentrationof chloride in water sample Mw using this equation

mol Ag+
= 1= MxVwx10-3 = MxVw
mol Cl- 1 Mwx20.00x10-3 Mwx20 so
M x Vw=Mw x20 or Mw= M x Vw
20
Mw= ? mol/L chloride in water sample= ? mmol/L
Mw=? g/L chloride in water sample
Mw=?ppm in water sample
Thanks

To calculate the concentration of chloride (Cl-) in a water sample, you can follow these steps:

1. Measure the volume of water sample used (Vw) in liters.
2. Prepare a solution of silver nitrate (AgNO3) with a known concentration (M) in moles per liter (mol/L).
3. Titrate the silver nitrate solution against the water sample until a white precipitate of silver chloride (AgCl) forms. The reaction between Ag+ and Cl- produces AgCl, and the number of moles of Ag+ used in the reaction is equal to the number of moles of Cl- in the water sample.
4. Record the volume of silver nitrate solution used (V) in liters.
5. Apply the equation mol Ag+ = M x Vw to calculate the number of moles of Ag+ used.
6. Since the stoichiometry of the reaction is 1:1 between Ag+ and Cl-, the number of moles of Cl- is equal to the number of moles of Ag+ used.
7. Convert the number of moles of Cl- to the desired units of concentration: mol/L, mmol/L, g/L, or ppm.

Let's go through an example calculation:

Example:
Suppose you used a silver nitrate solution with a concentration of 0.1 mol/L (M) and titrated 0.02 L (Vw) of water sample until 0.01 mol (mol Ag+) of silver nitrate was consumed.

1. Vw = 0.02 L (volume of water sample used).
2. M = 0.1 mol/L (concentration of silver nitrate solution).
3. V = 0.01 L (volume of silver nitrate solution used).

Using the equation mol Ag+ = M x Vw, we can calculate the moles of Ag+:

mol Ag+ = 0.1 mol/L x 0.02 L = 0.002 mol Ag+

Since the stoichiometry of the reaction is 1:1, the number of moles of Cl- is 0.002 mol as well.

To calculate the concentration of chloride in the water sample:
- In mol/L: Mw = 0.002 mol Cl-/0.02 L = 0.1 mol/L (concentration of chloride in water sample).
- In mmol/L: Mw = 0.1 mol/L x 1000 mmol/mol = 100 mmol/L.
- In g/L: Assuming the molar mass of chloride is 35.5 g/mol, Mw = 0.1 mol/L x 35.5 g/mol = 3.55 g/L.
- In ppm: 1 ppm = 1 mg/L, so Mw = 3.55 g/L x 1000 ppm/g = 3550 ppm.

Therefore, the concentration of chloride in the water sample is 0.1 mol/L, 100 mmol/L, 3.55 g/L, or 3550 ppm.