mol Ag+ =1 MxVx10-3 MxV

mol Cl- =1 0.01x20.00x103-= 0.2 so
MxV=0.2 o9r M=0.2
V
M=? mol/L silver nitrate Please
then volumes of silver nitrate required
2.23 2.26 2.43ml average Vw = ? ml

To find the concentration of silver nitrate (AgNO3) in terms of moles per liter (mol/L), you need to use the given information about the number of moles of Ag+ and Cl- ions.

From the given information:
mol Ag+ = 1M x V x 10^-3

To find the value of M (concentration of silver nitrate), you need to know the volume (V) in liters. Since the volume is not provided in the given information, it is not possible to determine the exact concentration of AgNO3.

As for the volume of silver nitrate required, you mentioned three values: 2.23 ml, 2.26 ml, and 2.43 ml. If you need to calculate the average volume (Vw), you can add these three values and divide by 3:

Vw = (2.23 ml + 2.26 ml + 2.43 ml) / 3 = 6.92 ml / 3 = 2.31 ml

Therefore, the average volume required is 2.31 ml.