A 0.130kg baseball pitched at 35.5 m/s is hit on a horizontal line drive straight back at the pitcher at 50.5 m/s .
Part a: If the contact time between bat and ball is 4.25×10^−3 , calculate the magnitude of the force (assumed to be constant) between the ball and bat.
part b)Determine the direction of the force exerted on a ball.
a)the force is directed towards the pitcher
b) the force is directed away from the pitcher.
physics- please respond - Delbarre, Saturday, June 2, 2012 at 1:56am
this exercise is conservation of linear momentum.
initial momentum: (0.130kg)(35.5)(i)
"remember linear momentum is vectorial.
i is vector direction and only the movement is in X"
Final momentum is :
I= 6.565(-i) - 4.615(i)
I= -6.565(i) - 4.615(i)
I= 11.18(-i) Kgm/s
F=I/t= 11.18(-i)Kgm/s/4.25×10^−3 s
F=2630.6 (Kgm/s² o N)
Enjoy the answer.
physics- please respond - Delbarre, Saturday, June 2, 2012 at 1:57am
the magnitude of the force is 2630.6 N
physics- please respond - katie, Saturday, June 2, 2012 at 2:26am
thank you !
physics- please respond - Helen, Sunday, June 3, 2012 at 3:21am
What about part B please?