Posted by katie on Friday, June 1, 2012 at 11:23pm.
this exercise is conservation of linear momentum.
initial momentum: (0.130kg)(35.5)(i)
"remember linear momentum is vectorial.
i is vector direction and only the movement is in X"
= 4.615(i)
Final momentum is :
= (0.130)(50.5)(-i)
=6.565(-i)
then I=impulse
I= 6.565(-i) - 4.615(i)
I= -6.565(i) - 4.615(i)
I= -11.18(i)
I= 11.18(-i) Kgm/s
I=F.t
F=I/t= 11.18(-i)Kgm/s/4.25×10^−3 s
F=2630.6 (Kgm/s² o N)
Enjoy the answer.
good luck
the magnitude of the force is 2630.6 N
thank you !
What about part B please?
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